If the block is in equilibrium, what is the reading in the scale in Newtons? Finance. Operations Management. Accounting. Leadership. 2) Im having a little trouble with this one. Spring Scales. menu. If the spring scales are calibrated in newtons, what do they read? Products. Have two people each hold one of the two spring scales. > What is the reading of a spring balance when a stretching force of 10 Newton is applied on the opposite sides at same time? Weight as in the force in newtons (N). Business. (sorry about the photo - dont know how to fix it) Homework Equations F=ma, W=mg The Attempt at a Solution 1) Seems easy enough. EXPLORE COLLECTIONS CREATE + back to brit + co. Sign In Sign Up. Ex 5.8 Two 100-N weights are attached to a spring scale as shown. Management. Two identical spring scales, like those used to weigh fish, or those found in physics class. Explore › guides › education › › You have a and m, you want F. F = 27.2*0.8 = 21.76N scale in (a) N. scale in (b) N. scale in (c) N. scale in (d) 2. So let’s understand more about Hooke’s law by examining how the Newton spring balance works. Does the scale read zero, 100 N, or 200 N -- or some other reading? The watermelon pushes down with a force of F = mg = 4.0kg*9.8 = ~ 40N. Introduction. 3. This refers to the TENSION force with which the spring scale pulls on something. Marketing. If used to measure friction force, it is only done so indirectly. The tension in the string is 100 N. This is the force the string must exert up on either of the 100-N weights at either end of the string. We use Newton's second law to solve this problem. In the figure below you can see the Newton spring balance in my laboratory. For this reason, a 1 kg reading on a spring scale refers to 9.8 Newtons of tension, and it scales proportionally. Hang the object to be measured from the spring scale hook. At the top of the spring balance there is a fixed end and at the bottom a free end which moves when a force is applied to it. The Newton Spring Balance. The systems shown below are in equilibrium (with m = 7.00 kg and θ = 27.0°). The scale reads the tension in the string. Newton's second law states that the force applied to a body produces a proportional acceleration. The scale on top would read slightly heavier due to also supporting the weight of the lower scale itself. Im pretty sure the balance would just read 98 N since the tension above equals the weight of the mass below. The forces acting on the system are the normal force by the spring scale and the downward weight of the woman. To Do and Notice. Ignore the masses of the pulleys and strings and assume the pulleys and the incline are frictionless. Solution for A block is attached to a spring scale. F = ma. Subjects. 2. Read the grams scale for weight. Material. This scale reads force in newtons. 1. 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